8m^2-7m-13=-10

Solution for 8m^2-7m-13=-10 equation:

8m^2-7m-13=-10

We move all terms to the left:

8m^2-7m-13-(-10)=0

We add all the numbers together, and all the variables

8m^2-7m-3=0

a = 8; b = -7; c = -3;
Δ = b2-4ac
Δ = -72-4·8·(-3)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{145}}{2*8}=\frac{7-\sqrt{145}}{16}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{145}}{2*8}=\frac{7+\sqrt{145}}{16}
$